Author Topic: Mulligan in Redemption?  (Read 14597 times)

Offline Eragon5

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Re: Mulligan in Redemption?
« Reply #50 on: March 22, 2015, 06:32:18 PM »
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I know a lot of ideas have been thrown out, but then what's one more  ;). All players get one mulligan per game. They leave out half their lost souls from their first hand, if any, rounding up. Opponent chooses which of those lost souls stay. No other penalties apply.

Just an idea. I'm not worried, I know you guys will find something that works. If this helps I'll be happy.
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Re: Mulligan in Redemption?
« Reply #51 on: March 22, 2015, 10:31:48 PM »
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I'm glad there is so much support for allowing Mulligans in this thread, because to be frank, there isn't a single good reason not to allow them. They contribute to the fun of the game by drastically reducing the chances that a player will lose from the beginning because they drew a bad hand. Considering the fact that any kind of Best 2 out of 3 format isn't really viable in Redemption because of game lengths, I think implementing Mulligans is a great way to mitigate the possibility of really bad luck knocking someone out of a tournament. I genuinely don't believe there is a single good reason to oppose them, because they maximize player skill and reduce luck, while making the game less frustrating for everyone at every skill level.

That said, I think we're seriously over-complicating what a mulligan should look like. The less conditions or steps that have to be taken, the better. Thus, I propose the following:

The player who has drawn the most souls gets to choose whether to Mulligan first. A player can choose to mulligan one time per game. All souls drawn stay out. The entire hand is shuffled and the player draws 8, replacing souls as necessary.

It's silly to punish people for bad luck, but it still deters people from attempting to trade an average hand for a good one, by threatening additional soul draw. I don't think there's a single good reason that Lost Souls should be put back in the deck.

Offline Alex_Olijar

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Re: Mulligan in Redemption?
« Reply #52 on: March 22, 2015, 10:34:02 PM »
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They increase luck, they just mitigate bad luck. There's a difference.

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Re: Mulligan in Redemption?
« Reply #53 on: March 22, 2015, 10:56:58 PM »
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They increase luck, they just mitigate bad luck. There's a difference.

You're splitting hairs. It reduces the chances of one player losing because they had bad luck, which is what the game cares about.

Offline Gabe

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Re: Mulligan in Redemption?
« Reply #54 on: March 22, 2015, 11:00:21 PM »
+1
The percentage of games actually lost to "bad luck" is extremely small. While most players don't actually realize it, most games are lost to inferior deck design and/or less than optimal choices during the game.
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Offline uthminister [BR]

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Re: Mulligan in Redemption?
« Reply #55 on: March 22, 2015, 11:06:27 PM »
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Wow...ouch! I mean, you are right, but laying down the honesty hammer. With that being the case generally speaking, increasing the chance of souls being available for players who have superior decks to rescue and players having better hands to make bad choices with would be nice.  8)

Offline EmJayBee83

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Re: Mulligan in Redemption?
« Reply #56 on: March 22, 2015, 11:10:49 PM »
+1
How about once at the start of the game either player may choose for any reason at all to shuffle all all cards back in their deck and redraw eight?

You appear to have missed my earlier statements about unrestricted mulligans involving drawn LSs, which I will never support even if I am trolled.
I have seen your earlier statements, I just do not understand the basis for them, and I am asking for someone to explain them to me.

As I said, on an opening draw of eight a player is more likely to draw 2+ LS then he/she is to draw 0 for any legal Redemption deck. Given this, the idea that  mulligans would be a cause of soul drought appears to have a somewhat dubious basis.

You base your categorical opposition for open mulligans on concerns about young players having fun. How do they feel about games where they draw three or more lost souls in their opening hands and have no way to prevent being overrun and losing in three turns?  Do they enjoy those games?

Quote
Unless you are saying we should have games rules to prevent you personally from playing poorly, ...

General trolling....  :(
Actually, quite the opposite. This was Olijar-specific trolling made in direct response to his trolling of the thread.

The percentage of games actually lost to "bad luck" is extremely small.
While true in general, this is grossly oversimplified. The whole basis for ANB-reset decks is to take advantage of opening draw variance. There is a reason why back in the day I was able to beat clearly superior players on a regular basis using those decks.
« Last Edit: March 22, 2015, 11:17:57 PM by EmJayBee83 »

Offline YourMathTeacher

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Re: Mulligan in Redemption?
« Reply #57 on: March 22, 2015, 11:24:50 PM »
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As I said, on an opening draw of eight a player is more likely to draw 2+ LS then he/she is to draw 0 for any legal Redemption deck.

Obviously the probability of drawing 2 or more LSs is going to be higher than drawing none, since you are comparing 7 combined outcomes to 1. Since there can only be one outcome of the two trials, you would have to compare the probability of any one of the outcomes of 2 or more LSs to none, rather than all of them at once. If you do a proper comparison, then the probability of two versus none would be the closest. The probability of 3,4,5,6,7 or 8 LSs on the initial draw would certainly be lower individually than drawing none. I doubt you would argue that the probability of drawing 8 LSs is higher than the probability of drawing none.  ;)
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Offline Alex_Olijar

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Re: Mulligan in Redemption?
« Reply #58 on: March 22, 2015, 11:25:48 PM »
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Drawing no lost souls is so obscenely strong that I'm willing to end up with 2-7 instead of just 1 if it gives me the opportunity to have 0.

Offline YourMathTeacher

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Re: Mulligan in Redemption?
« Reply #59 on: March 22, 2015, 11:34:49 PM »
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You base your categorical opposition for open mulligans on concerns about young players having fun. How do they feel about games where they draw three or more lost souls in their opening hands and have no way to prevent being overrun and losing in three turns?  Do they enjoy those games?

Yes, actually, they do!   ;D At least they get to play their cards and have battles. Soul Drought causes them to discard a bunch of cards each turn in the Discard Phase.....  woo-hoo...

Actually, quite the opposite. This was Olijar-specific trolling made in direct response to his trolling of the thread.

Actually, I was trolling....  :maul:
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Offline jesse

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Re: Mulligan in Redemption?
« Reply #60 on: March 22, 2015, 11:55:45 PM »
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Something to consider: will allowing mulligans change deck-building strategy?

I think it would...instead of having a balanced deck, it would perhaps lead to decks that are skewed in some advantageous way, with its player mulliganing until they get that starting advantage. Good and proper deck-building should consider how to overcome a difficult start, how to survive and bounce back. Perhaps allowing a mulligan would actually have the opposite of the intended result and actually cause superior deck-builders & players to lose more.

Think about it...if you are playing the national champ, won't you mulligan if you get anything less than a fantastic starting hand? Especially if there's no cost? Is it fair to the national champ, who probably doesn't need a mulligan no matter what they draw? Perhaps this is why if we do allow a mulligan, there should be a cost after all...
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Offline ChristianSoldier

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Re: Mulligan in Redemption?
« Reply #61 on: March 23, 2015, 01:22:27 AM »
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Something to consider: will allowing mulligans change deck-building strategy?

I think it would...instead of having a balanced deck, it would perhaps lead to decks that are skewed in some advantageous way, with its player mulliganing until they get that starting advantage. Good and proper deck-building should consider how to overcome a difficult start, how to survive and bounce back. Perhaps allowing a mulligan would actually have the opposite of the intended result and actually cause superior deck-builders & players to lose more.

Think about it...if you are playing the national champ, won't you mulligan if you get anything less than a fantastic starting hand? Especially if there's no cost? Is it fair to the national champ, who probably doesn't need a mulligan no matter what they draw? Perhaps this is why if we do allow a mulligan, there should be a cost after all...

First of all, no one is suggesting unlimited free mulligans (as far as I know, because that would just be silly) either a single "free" mulligan or having some kind of stacking detriment (usually losing cards in the starting hand).

Next I will suggest that mulligans will have little effect on deck building, since they likely won't be used in an attempt to turn an okay hand into a good one, but to turn a really bad hand into a workable one, by giving more opportunities to have a decent hand.

As I said, on an opening draw of eight a player is more likely to draw 2+ LS then he/she is to draw 0 for any legal Redemption deck.

Obviously the probability of drawing 2 or more LSs is going to be higher than drawing none, since you are comparing 7 combined outcomes to 1. Since there can only be one outcome of the two trials, you would have to compare the probability of any one of the outcomes of 2 or more LSs to none, rather than all of them at once. If you do a proper comparison, then the probability of two versus none would be the closest. The probability of 3,4,5,6,7 or 8 LSs on the initial draw would certainly be lower individually than drawing none. I doubt you would argue that the probability of drawing 8 LSs is higher than the probability of drawing none.  ;)

Actually EmJayBee83's point makes sense (assuming his math is correct, which I'm trying to figure out, but am having some difficulties when I add it up sum the probabilities of drawing each number of lost souls from 0 to 7 and get 1.1. But all EmJayBee83 cares about is 0 compared to 2 or more, since 3 or 4 would also be just as (or more so unfavorable outcomes) so comparing 0 to 2+ makes perfect sense.
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Offline jesse

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Re: Mulligan in Redemption?
« Reply #62 on: March 23, 2015, 03:32:16 AM »
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So then how about:

1. Both players draw as normal and lay out LSs (which will stay out).
2. The player with the least LSs in territory chooses first if they want to mulligan (their one and only opportunity).
3. To mulligan, simply reveal your hand, then shuffle it, and redraw 8.
4. The player with the next highest LSs can now choose to mulligan or not (also their only opportunity).

This would hopefully encourage players to only mulligan to get emergency defense, as you wouldn't want to mulligan with 0 LSs only to likely put 1+ out there while revealing 8, nor would you want to with 1+ LSs lose some defense you already drew, especially at the cost of revealing that defense.

If you have less LSs to start, you are at an advantage (especially with 0), so you might want to stand pat instead of revealing your hand (which is to an extent like revealing your deck). Whereas if you have more LSs than your opponent(s), defense is top priority and would thus be the mulligan motivation...which is what we want, right? For the mulligan to be more of an emergency choice versus used to gain a dominant starting position.
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Offline kram1138

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Re: Mulligan in Redemption?
« Reply #63 on: March 23, 2015, 09:14:55 AM »
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From what I understand, the point of a mulligan would be to speed up the game (no offence) or make the game more competitive and balanced (lost souls, but no defence). If there were NO penalties or restrictions, it would sometimes be used for those reasons, but what I think would happen, would be that it would be used whenever someone draws a lost soul at all, unless they had a really strong defence as well. This would neither speed up the game nor make it more competitive. It shouldn't be the norm, it should be a leader ditch attempt to get a defence if you have none but drew lost souls.

As such, as long as at least one lost soul stays out, I would be fine with it. I don't think anything else would be required, since that would solve the main problem of it being used to induce drought. But otherwise I would be strongly opposed.
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Offline EmJayBee83

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Re: Mulligan in Redemption?
« Reply #64 on: March 23, 2015, 09:44:49 AM »
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...it [a no restriction mulligan--mjb] would be used whenever someone draws a lost soul at all,...
If you had one LS out, and you took a free mulligan, your chances are better to have a greater number of LS out afterwards than they are to have fewer LS out. If you are really trying to cause LS soul drought this would be a sub-optimal decision.

As I said, on an opening draw of eight a player is more likely to draw 2+ LS then he/she is to draw 0 for any legal Redemption deck.
Obviously the probability of drawing 2 or more LSs is going to be higher than drawing none, since you are comparing 7 combined outcomes to 1.
As a direct counter-example... In a legal redemption deck you are about 30% more likely to draw 1 Lost Soul than you are to draw 2 or more. These results have much more to do the relative probability of the draw distribution as opposed to the number of outcomes.

Quote
If you do a proper comparison, then the probability of two versus none would be the closest.
I am attempting to replicate what players would do in actual practice (which I feel is the best comparison). If you are trying to determine a strategy for taking a mulligan strictly to prevent LS flood, a player would set a minimum number of LS drawn as a trigger--not set different rules for each number. Alex's and Kram1138's proposed heuristic is a prime example of that.

(assuming his math is correct, which I'm trying to figure out, but am having some difficulties when I add it up sum the probabilities of drawing each number of lost souls from 0 to 7 and get 1.1.
Given the Redemption draw mechanic of ignoring LSs as drawn, it is way simpler to use a Monte Carlo simulation to determine the relative probabilities than to attempt to calculate from first principles. (This just meant as a helpful tip.)

Offline kram1138

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Re: Mulligan in Redemption?
« Reply #65 on: March 23, 2015, 10:39:38 AM »
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...it [a no restriction mulligan--mjb] would be used whenever someone draws a lost soul at all,...
If you had one LS out, and you took a free mulligan, your chances are better to have a greater number of LS out afterwards than they are to have fewer LS out. If you are really trying to cause LS soul drought this would be a sub-optimal decision.

As I said, on an opening draw of eight a player is more likely to draw 2+ LS then he/she is to draw 0 for any legal Redemption deck.
Obviously the probability of drawing 2 or more LSs is going to be higher than drawing none, since you are comparing 7 combined outcomes to 1.
As a direct counter-example... In a legal redemption deck you are about 30% more likely to draw 1 Lost Soul than you are to draw 2 or more. These results have much more to do the relative probability of the draw distribution as opposed to the number of outcomes.

To put numbers to this discussion, with a 50 card deck with 7 lost souls, the probability of drawing 1 lost soul is 42%. The probability of drawing 2 or more is 31%. The probability of drawing no lost souls is 27%. I'm not sure where you're getting that 30% more likely to draw 1 than 2+. 42 - 31 does not equal 30%. You are 11% more likely to draw 1 than to draw 2 or more. So, since the chances of getting 2+ lost souls on a redraw is not much higher than getting none, the benefit of getting none would arguably be worth the chance, compared to the cost of getting 2+ when you had 1 before. But even still, if I draw 2+ ls, there is still a 70% that I decrease the number of lost souls I drew if I mulligan.

Once you consider a 56 card deck with 7 lost souls, the probabilities are 1: 42%, 2+: 26%, 0: 32%. In this case you're 6% more likely to draw none than 2+, and probability would say to mulligan every time you draw a lost soul, unless you had a really strong defense.

And the numbers are essentially the same for T2, except that for 105 cards, the chances of drawing 0 are only 2-3% higher than 2+.
« Last Edit: March 23, 2015, 10:44:45 AM by kram1138 »
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Offline Knoxyouthpastor

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Re: Mulligan in Redemption?
« Reply #66 on: March 23, 2015, 10:54:50 AM »
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I am not a fan of a mulligan personally except under one condition, on initial draw at beginning of game he/she draws 5 or more lost souls. Then the shuffle and draw one less would be good as long as you keep one LS in play. This would be the only scenario I would support. There are many ways to manipulate your LS's in today's game, especially with LS special abilities, sites, shuffling, protection, and so forth. I believe it will only cause more frustration if you can shuffle your hand just because you don't like it on your initial draw. It's part of the game, that's why they call it "luck of the draw". It happens and with so much speed and ways to go get cards you need, you'll get what you need anyway. Just my thoughts. :-\
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Re: Mulligan in Redemption?
« Reply #67 on: March 23, 2015, 11:18:44 AM »
+1
So, I seem to have missed this thread... what about taking a page from Hearthstone's book?

You draw 8 as usual (souls going into play and cards draw to replace them), then at that point, you can decide what cards you want to replace. You shuffle those cards back in and re-draw to replace them (souls go into play and you draw to replace them)

Being able to keep some cards while replacing others will give both players a chance at having a strong opening hand. You can't use it to force a soul drought, and both players end up with 8 cards.

Offline EmJayBee83

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Re: Mulligan in Redemption?
« Reply #68 on: March 23, 2015, 11:43:34 AM »
0
As a direct counter-example... In a legal redemption deck you are about 30% more likely to draw 1 Lost Soul than you are to draw 2 or more.
To put numbers to this discussion, with a 50 card deck with 7 lost souls, the probability of drawing 1 lost soul is 42%. The probability of drawing 2 or more is 31%. The probability of drawing no lost souls is 27%.
Thank you for providing the number.  I wanted someone else to post them as a cross check of what I did.

Quote
I'm not sure where you're getting that 30% more likely to draw 1 than 2+. 42 - 31 does not equal 30%. You are 11% more likely to draw 1 than to draw 2 or more.
You are not correctly calculating the comparison of the the likelihood of the two specific events. If I flipped two coins and asked you you how much more likely you were to get one head and one tail (50%) than you were to get two tails (25%), the correct answer--well not correct per se, but the standard answer--is twice as likely (50%/25%) , not 25% more likely (50% - 25%).

So, 42% / 31% = 1.35--which means you are 35% more likely to see 1 LS than you are to see 2+ LS. (This is actually higher than my stated value, because I mis-remembered the exact numbers.)
« Last Edit: March 23, 2015, 11:48:04 AM by EmJayBee83 »

Offline kram1138

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Re: Mulligan in Redemption?
« Reply #69 on: March 23, 2015, 11:58:24 AM »
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As a direct counter-example... In a legal redemption deck you are about 30% more likely to draw 1 Lost Soul than you are to draw 2 or more.
To put numbers to this discussion, with a 50 card deck with 7 lost souls, the probability of drawing 1 lost soul is 42%. The probability of drawing 2 or more is 31%. The probability of drawing no lost souls is 27%.
Thank you for providing the number.  I wanted someone else to post them as a cross check of what I did.
Rather than going back and actually having to remember how to calculate probabilities, I wrote a quick program that simulated drawing over 1,000,000 trials or so. Those numbers might not be exact, but with a million trials, its close enough that no one cares.

Quote
I'm not sure where you're getting that 30% more likely to draw 1 than 2+. 42 - 31 does not equal 30%. You are 11% more likely to draw 1 than to draw 2 or more.
You are not correctly calculating the comparison of the the likelihood of the two specific events. If I flipped two coins and asked you you how much more likely you were to get one head and one tail (50%) than you were to get two tails (25%), the correct answer--well not correct per se, but the standard answer--is twice as likely (50%/25%) , not 25% more likely (50% - 25%).

So, 42% / 31% = 1.35--which means you are 35% more likely to see 1 LS than you are to see 2+ LS. (This is actually higher than my stated value, because I mis-remembered the exact numbers.)
Ah. That's what you meant by it. Then yes, you are correct. But again, this is dependent upon the number of cards and lost souls in your deck.

And to restate my original position, I would prefer no mulligan, but if it was going to be done, keeping a ls would be preferable.
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Offline EmJayBee83

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Re: Mulligan in Redemption?
« Reply #70 on: March 23, 2015, 12:54:31 PM »
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Rather than going back and actually having to remember how to calculate probabilities, I wrote a quick program that simulated drawing over 1,000,000 trials or so.
Me too!  (Even the same number of trials. ;) )

Hey, Kids, here is a pro-tip for you...Markov chains are much easier in Monte Carlo.

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Re: Mulligan in Redemption?
« Reply #71 on: March 23, 2015, 01:46:59 PM »
+2
The percentage of games actually lost to "bad luck" is extremely small. While most players don't actually realize it, most games are lost to inferior deck design and/or less than optimal choices during the game.

I would argue that the existence of Son of God and New Jerusalem (along with dominants in general) makes that less true for Redemption than it is for other CCGs. Quite a few games come down to who draws (or searches) one or both of them first.

Offline EmJayBee83

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Re: Mulligan in Redemption?
« Reply #72 on: March 23, 2015, 03:32:51 PM »
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I just ran a Monte Carlo for the Olijar strategy (i.e., take a free mulligan whenever you draw any number of Lost Souls). Frankly it is disastrous.  Over 75% of games would start with at least one player having no lost souls available for rescue.

Oh well...

Offline YourMathTeacher

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Re: Mulligan in Redemption?
« Reply #73 on: March 23, 2015, 03:38:53 PM »
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So, 42% / 31% = 1.35--which means you are 35% more likely to see 1 LS than you are to see 2+ LS. (This is actually higher than my stated value, because I mis-remembered the exact numbers.)

But again, as kram pointed out, you are using a 50-card deck for your argument. A 56-card deck would not have that same result, since you are more likely to draw none than to draw 2+. A 50 card deck in Type 1 is more of an exception because there are 7 LSs per 50 instead of 7 LSs per 56. This exception would occur each time a player added one LS to reach the next threshold (i.e. 8 LSs in a 57 card deck). I would argue that those people want to draw LSs for their strategy, therefore it is not a proper example for this discussion. Since I am arguing on behalf of new/young players, they are far more likely to have a 56-card deck than a 50-card deck, unless someone instructed them to make their deck smaller.
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Offline EmJayBee83

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Re: Mulligan in Redemption?
« Reply #74 on: March 23, 2015, 03:53:05 PM »
0
So, 42% / 31% = 1.35--which means you are 35% more likely to see 1 LS than you are to see 2+ LS. (This is actually higher than my stated value, because I mis-remembered the exact numbers.)

But again, as kram pointed out, you are using a 50-card deck for your argument. A 56-card deck would not have that same result, since you are more likely to draw none than to draw 2+.
Just for the record, Kram's number for the 56-card deck are off substantially for the 1 and 2+ cases.  For the 56-card deck you get (0,31.8%), (1,37.0%), and (2+,31.2). So yes, there is a 0.6% difference--so after 150 games you would expect to have one more 0-lost soul game than 2+ lost soul game. The 56 card deck is the only legal Redemption deck that would exhibit this inversion because it is the only deck that allows a 7:1 non-soul to soul ratio.

Not that any of this is really relevant to the discussion of mulligan rules any more (see my last post).
« Last Edit: March 23, 2015, 03:57:38 PM by EmJayBee83 »

 


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