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A four-round ten player tournament is no different than one with 14 or 16 players, in that four rounds will determine a winner, in most circumstances going undefeated is not 100% required
But it's a threshhold for a reason. A four-round ten player tournament is no different than one with 14 or 16 players, in that four rounds will determine a winner, in most circumstances going undefeated is not 100% required, and in the one case where it is, the winner defeated everyone in front of him, no one else was undefeated, and there are so many different scenarios once you have 16+ players that the number of rounds before every one-loss player gets one crack at the champion could as much as double the play time.
For State and higher can we up the minimum number of required rounds to be at least one more than is listed currently.
Don't you have to pull the plug at some point? I can see the logic in recommending extra rounds in certain situations but I don't agree with the idea of changing the rule to fit the exception.
For State and higher can we up the minimum number of required rounds to be at least one more than is listed currently. Simply put, if you play only the minimum number of rounds listed the tournament is effectively a single-elimination event. The tournament host's guide speaks all about the advantages of Swiss-style tourneys compared to single elimination, but all of that is lost if you only host the current minimum number of required rounds.
Actually I think that most of the time the winner will be undefeated. After 1 round, there would be 5 undefeated players matching up. After 2 rounds, there would be 2-3 undefeated players matching up. After 3 rounds there would be 1-2 undefeated players matching up. If that number was 2, then there would have to be an undefeated player. The only way for this to not be the case is if someone lost a game, worked their way back up to the championship game in the 4th round and defeated the last undefeated player (or multiple timeouts).
I can't see that in the general case adding a single round is going to double play time. Nor can I understand why anyone would think that I am asking that "every one-loss player gets one crack at the champion."
I understand that it could add to the burdens of the host.
How do you figure that the person playing either of the top two players in the second round placing are the best players in that category?
It is not quite as apparent in a game to only 5 points, but if we played to 10,000 points, it would be quite clear that the top player (getting 9,993 points in the first game) and the 2nd best player (getting 9,225 points in the first game) would be playing against each other in the second round. This is the design of swiss style - not just another pairing.
Quote from: The Schaef on June 30, 2009, 11:53:54 AMA four-round ten player tournament is no different than one with 14 or 16 players, in that four rounds will determine a winner, in most circumstances going undefeated is not 100% requiredActually I think that most of the time the winner will be undefeated. After 1 round, there would be 5 undefeated players matching up. After 2 rounds, there would be 2-3 undefeated players matching up. After 3 rounds there would be 1-2 undefeated players matching up. If that number was 2, then there would have to be an undefeated player. The only way for this to not be the case is if someone lost a game, worked their way back up to the championship game in the 4th round and defeated the last undefeated player (or multiple timeouts).Based on the experience of people who have been to a lot of tournaments (Pol, Kirk, etc.), this just doesn't happen very often.