Author Topic: A dominant everyone can agree on: (Read 6157 times)

SomeKittens · « **on:** September 12, 2010, 01:40:08 PM »

Meaningless!
Evil dominant

Discard any card in play, set aside, in deck, discard pile or Land of Redemption with a 2 John reference

Ecclesiastes 1:2 "Meaningless! Meaningless!"
says the Teacher.
"Utterly meaningless!
Everything is meaningless."

I'd like the card image to be the Redemption logo divided by zero. Don't feel like making the full 'shoop.

The Warrior · « **Reply #1 on:** September 12, 2010, 01:41:18 PM »

Minister Polarius · « **Reply #2 on:** September 12, 2010, 04:11:34 PM »

Pancakes are made out of pancakes.

SomeKittens · « **Reply #3 on:** September 12, 2010, 04:30:11 PM »

But that one actually does something...

Minister Polarius · « **Reply #4 on:** September 12, 2010, 04:47:06 PM »

FioHP is useful now. ET+That=win the battle.

The M · « **Reply #5 on:** September 12, 2010, 05:00:09 PM »

Meaningless 3: Protect all lost souls from rescue for three turns. Decrease all characters in play by X.
X = number of no special ability O.T. human heroes in your territory.

The Warrior · « **Reply #6 on:** September 12, 2010, 05:44:46 PM »

SomeKittens · « **Reply #7 on:** September 12, 2010, 06:02:44 PM »

Here's the one we need:
Hyper-Powerful Admin:
Negate and Discard all spam currently in thread.

I like Meaningless enough, I think I'll make it.

CJSports · « **Reply #8 on:** September 13, 2010, 06:30:45 PM »

What cards are 3rd John.

browarod · « **Reply #9 on:** September 13, 2010, 06:54:29 PM »

Quote from: CJSports on September 13, 2010, 06:30:45 PM

What cards are 3rd John.

There aren't any, that's the point of the card, lol.

CJSports · « **Reply #10 on:** September 13, 2010, 07:10:40 PM »

Ohhhhhhhhhhh ok gotcha, now i love this card.

SomeKittens · « **Reply #11 on:** September 13, 2010, 07:14:56 PM »

Though watch a super-powerful 3 John card come through in Apostles 3 next year.

browarod · « **Reply #12 on:** September 13, 2010, 07:19:29 PM »

So, what exactly happens when you discard a card already in the discard pile?

Professoralstad · « **Reply #13 on:** September 13, 2010, 09:56:25 PM »

Quote from: browarod on September 13, 2010, 06:54:29 PM

Quote from: CJSports on September 13, 2010, 06:30:45 PM
What cards are 3rd John.
There aren't any, that's the point of the card, lol.

You better come up with a proof that 2=0 real quick, or Imma call you a liar.

Rawrlolsauce! · « **Reply #14 on:** September 13, 2010, 10:05:48 PM »

a = b
a – b = 0
(a – b)/(a – b) = 0 / (a-b)
1*2 = 0*2
2=0

INB4DIVIDEBY0

Master KChief · « **Reply #15 on:** September 13, 2010, 10:09:33 PM »

so now, the point of this thread is meaningless.

Minister Polarius · « **Reply #16 on:** September 13, 2010, 10:11:15 PM »

Isn't it II John?

Josh · « **Reply #17 on:** September 13, 2010, 10:13:11 PM »

Quote from: Rawrlolsauce! on September 13, 2010, 10:05:48 PM

a = b
a – b = 0
(a – b)/(a – b) = 0 / (a-b)
1*2 = 0*2
2=0

INB4DIVIDEBY0

I'm doubting some of your transitions in that equality. Let me try:

a = b
a^2 = ab
a^2 - b^2 = ab - b^2
Factor difference of squares...
(a - b)(a + b) = b(a-b)
Divide by common denominator...
a + b = b
Substitute b for a, since a = b...
b + b = b
2b = b
2 = 1

It's not quite 2 = 0, but with a little manipulation, you could probably get there

browarod · « **Reply #18 on:** September 13, 2010, 10:48:27 PM »

/facepalm

I really need to shoot the thing in my head that's pretending to be my brain. Then I need to find my actual brain again.

Professoralstad · « **Reply #19 on:** September 13, 2010, 10:49:27 PM »

Quote from: Minister Polarius on September 13, 2010, 10:11:15 PM

Isn't it II John?

Yes.

Prof Underwood · « **Reply #20 on:** September 13, 2010, 11:46:49 PM »

~~And here we have the problem. (a-b)(a+b) is really a^2 - 2ab - b^2. You are missing the middle term.~~
Oops, that must be why I teach science and not math.

Quote from: jmhartz on September 13, 2010, 10:13:11 PM

(a - b)(a + b) = b(a-b)
Divide by common denominator...
a + b = b

There's the real problem. The "common denominator" there is (a-b) which is 0 based on the given that a=b. Therefore you are dividing by zero which is impossible. Very nicely done though

SomeKittens · « **Reply #21 on:** September 14, 2010, 12:29:43 AM »

I put 2 John in the first place. What are you guys talking about?

WAR IS PEACE, FREEDOM IS SLAVERY, IGNORANCE IS STRENGTH

Josh · « **Reply #22 on:** September 14, 2010, 08:10:08 AM »

Quote from: Prof Underwood on September 13, 2010, 11:46:49 PM

Quote from: jmhartz on September 13, 2010, 10:13:11 PM
a^2 - b^2
Factor difference of squares...
(a - b)(a + b)
And here we have the problem. (a-b)(a+b) is really a^2 - 2ab - b^2. You are missing the middle term.

Not quite. Using FOIL method:
(a + b)(a - b) = a^2 - ab + ab - b^2
Combine like terms...
a^2 - b^2

Bonus points go to the person who can name the flaw in my equality

browarod · « **Reply #23 on:** September 14, 2010, 09:18:15 AM »

You mean besides dividing by 0?

Josh · « **Reply #24 on:** September 14, 2010, 12:52:44 PM »

Congratulations to browarod and Prof U for solving the riddle! browarod was first, so he wins 9001 bonus points. Unfortunately bonus points are pretty much worthless; in fact, they are worth $-1/20th of one cent, meaning you now owe me $4.50.

News:

Author Topic: A dominant everyone can agree on: (Read 6157 times)

browarod

browarod

Rawrlolsauce!

browarod

browarod